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Pearl Ring | The Best of Pearl Jewelry: Wedding cost? Flat. Fewer marry. Wedding boom over...: Wedding cost? Flat. Fewer marry. Wedding boom over? Christian Science Monitor - Jun. 4, 2012 Her David's Bridal wedding gown...
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Not whether we have a right to say that at a certain size
spheroid pressure will be strong enough to produce
the transition to the liquid state in any other place but the centre, or
in other words, with decreasing temperature and increasing pressure
United conditions of pressure and temperature required for a transition in
liquid state primarily will be achieved in the center? If so,
the transition to the liquid state, beginning at the center, will be there
spread to a circle, and, due to the fact of law that a solid body,
under pressure, require a higher temperature at which they
can melt than when they are not exposed to the pressure of the transition in
solid state, very possibly, will start in center and spread to
the later period similarly to the outer parts in this case
the end you get this condition, which, according to sir William
Thomson, exists on the Earth. But now imagine that instead of this
spheroid - spheroid we have, say, twenty or thirty times what
happens then? Despite the mixing currents, the temperature at the centre
always be higher than anywhere else, and in the cooling process
"critical point" temperature is reached sooner in the outer parts.
Although on the surface does not exist the required pressure, however
in a large spheroid, obviously, should be such depth under the surface
the pressure will be enough if the temperature is sufficiently low. Here
we can conclude that somewhere between the center and surface in the proposed
larger spheroid will be the condition described by Professor Andrews, in which
"shimmering streams" of liquid float in gaseous matter of equal
density. It is also possible to conclude that gradually, as you continue this
process, these jets will become more abundant, whereas intervals with
gaseous matter will be reduced until eventually the liquid
is just a space. Thus, the result is
molten shell containing a gaseous nucleus is the same with her
density on the surface of contact and more dense in the center
molten shell which will slowly thicken as a result
buildup both inside and outside.
You it is fair to conclude that in the end on this
molten shell formed a solid crust. To the objection that
curing may not start on the surface, because the resulting
the solid part should go down, you can give two answers. First,
some metals expand when curing and therefore have to swim.
Secondly, because the environment of the intended spheroid would be
of the gases and the metalloids in the molten shell constantly accumulates be
compounds of these gases and metalloids, or each other, or with metals,
and the crust, consisting of oxide, chloride and sulfur compounds, etc., having
much lower specific gravity than molten shell, easy
would support it.
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