If the mass of nebulous matter, the approaching spiral to the Central spheroid and in the end acceding at a tangent consists of parts having the same absolute speed, then when it connects with the Equatorial the circumference of the spheroid and will move with her, her outer part acquire a smaller angular velocity than the inner. It follows that if at the same angular velocity of the outer and inner parts the breakaway ring is the desire to rotate around the axis in the same direction, as in orbit, we can conclude that at lower corner the speed the outer parts of the ring than the inner parts, the result the desire for rotation in the reverse direction. Another very important the fact is, the sectional shape of the ring; form this in each individual the case was supposed to be more or less different. To explain this, it is necessary to resort, for example. Imagine an orange, and the point where the orange belonged to the stem and to the Cup, will represent the poles. Cut from peel around the equator of the strip. This strip, if it is put on the table so that the ends thereof converge, forms a ring like a Hoop of a barrel, ring, whose thickness in the direction of its diameter is very small, but whose width in a direction perpendicular to its diameter, a rather significant. Suppose now that instead of orange, which is spheroid, very little flattened, we'll take a flattened spheroid with the form is not too convex, lenticular glass. If the edges or the equator of the lenticular glass that we cut off a small ring, it the ring will be different from the previous one in the sense that the greatest its thickness will be in the direction of its diameter, not in line intersecting the diameter at right angles: this will ring a few approaching the form of a disk, only much more subtle.
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If the mass of nebulous matter,
the approaching spiral to the Central spheroid and in the end
acceding at a tangent consists of parts having
the same absolute speed, then when it connects with the Equatorial
the circumference of the spheroid and will move with her, her outer part
acquire a smaller angular velocity than the inner. It follows that
if at the same angular velocity of the outer and inner parts
the breakaway ring is the desire to rotate around the axis in the same
direction, as in orbit, we can conclude that at lower corner
the speed the outer parts of the ring than the inner parts, the result
the desire for rotation in the reverse direction. Another very important
the fact is, the sectional shape of the ring; form this in each individual
the case was supposed to be more or less different. To explain this,
it is necessary to resort, for example. Imagine an orange, and the point where
the orange belonged to the stem and to the Cup, will represent the poles. Cut from
peel around the equator of the strip. This strip, if it is put on the table
so that the ends thereof converge, forms a ring like a Hoop of a barrel,
ring, whose thickness in the direction of its diameter is very small,
but whose width in a direction perpendicular to its diameter, a rather
significant. Suppose now that instead of orange, which is
spheroid, very little flattened, we'll take a flattened spheroid with
the form is not too convex, lenticular glass. If the edges or
the equator of the lenticular glass that we cut off a small ring, it
the ring will be different from the previous one in the sense that the greatest
its thickness will be in the direction of its diameter, not in line
intersecting the diameter at right angles: this will ring a few
approaching the form of a disk, only much more subtle.
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